Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Idea: I used the brute force method by comparing the substrings one by one. There are other algorithms, e.g. KMP which can achieve better performance.
Time: O(n^2) Space: O(1)
Code:
public class Solution {
public int strStr(String haystack, String needle) {
for(int i=0;i<haystack.length()-needle.length()+1;i++)
{
int j=0;
for(j=0;j<needle.length();j++)
{
if(haystack.charAt(i+j)!=needle.charAt(j))
break;
}
if(j==needle.length())
return i;
}
return -1;
}
}
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